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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

1 vote

Natural extension of the Gauss map

Partial answer. I imagine that you mean a map $\overline{G}$ which sends $([0;a_1,a_2,\ldots],[0;a_0,a_{-1},\ldots])$ on $([0;a_2,a_3,\ldots],[0;a_1,a_0,\ldots])$. If yes, we have a simple formula $$\ …
Christophe Leuridan's user avatar
7 votes

Square root of prime numbers

My impression is that you have developed $(x_0-\sqrt{S})^{2^n}$ with Newton binomial formula, separated the terms with even index from the terms with odd index to get an expression of the form $A_n-\s …
Christophe Leuridan's user avatar
1 vote

Growth of the "cube of square root" function

For $-1<h<1$, $$(1+h)^{3/2}+(1-h)^{3/2} = 2 \sum_{n=0}^{+\infty}{3/2 \choose 2n}h^{2n},$$ where $${3/2 \choose 2n} = \prod_{k=1}^ {2n} \frac{5/2-k}{k}.$$ For $n \ge 1$, since $(-1)^{2n-2}=1$, we get $ …
Christophe Leuridan's user avatar
7 votes
Accepted

Central limit theorem for irrational rotations

I am surprised by the question. The sums are bounded if $\alpha \ne 1$, since for every $n \ge 1$, $$\Big|\sum_{k=1}^n \Re R_\alpha^k z \Big| = \Big|\Re \Big(\sum_{k=1}^n R_\alpha^k z \Big) \Big| = \B …
Christophe Leuridan's user avatar
1 vote
Accepted

Convergence and roots of alternating periodic infinite series

I prove the convergence of the series. For $n \ge 1$, let $$S_n = \sum_{k=1}^n k^{-i\beta-\alpha} \text{ and } S'_n = \sum_{k=1}^n (-1)^ {k-1} k^{-i\beta-\alpha}$$ Then $$S_{2n}-S'_{2n} = 2 \sum_{k=1} …
Christophe Leuridan's user avatar