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Topologically Ordered Families of Disjoint Cantor Sets in $I$?

Suppose that we have an uncountable collection $C_\alpha$ of disjoint Cantor Sets contained in the closed unit interval $I$. Suppose we have ordered the indices $\alpha \in [0,1]$ as well. Then is ...
John Samples's user avatar
19 votes
1 answer
545 views

Can an injective $f: \Bbb{R}^m \to \Bbb{R}^n$ have a closed graph for $m>n$?

Question. Suppose $m>n$ are positive integers. Is there a one-to-one $f: \Bbb{R}^m \to \Bbb{R}^n$ such that the graph $\Gamma_f$ of $f$ is closed in $\Bbb{R}^{m+n}$? Remark 1. The answer to the ...
Ali Enayat's user avatar
  • 16.5k
12 votes
0 answers
171 views

A connected Borel subgroup of the plane

It is known that the complex plane $\mathbb C$ contain dense connected (additive) subgroups with dense complement but each dense path-connected subgroup of $\mathbb C$ necessarily coincides with $\...
Taras Banakh's user avatar
  • 40.2k
26 votes
1 answer
4k views

Closed balls vs closure of open balls

We work in a separable metric space $(X,d)$. With $\overline{B}(x,r)$ I denote the closed ball around $x$ of radius $r$, and with $cl \ B(x,r)$ I denote the closure of the open ball. Clearly, we ...
Arno's user avatar
  • 4,096
3 votes
1 answer
117 views

Nice representation of open sets in $\sigma$-algebras in certain circumstances

Let $(X,\tau)$ be a topological space. For a given topological base $\mathcal{E}$ for $\tau$, let us denote Bor$(\mathcal{E})$, by the smallest $\sigma$-algebra containing $\mathcal{E}$. Q. Assume ...
ABB's user avatar
  • 3,898
4 votes
1 answer
111 views

Nice arrangement of open sets in $\sigma$-algebras

Let $X$ be a topological space and $\mathcal{E}$ be a topological base for $X$. Let us denote Bor$(\mathcal{E})$, by the smallest $\sigma$-algebra containing $\mathcal{E}$. Q. Let $O$ be an open ...
ABB's user avatar
  • 3,898
1 vote
0 answers
85 views

An example of a Borel map of the first class

Let $X,Y$ be compact metric spaces, $2^X$ the set of all closed subsets of $X$ and $f:X\to Y$ be a 1st class Borel mapping. Im trying to check Borel class of mapping $G:2^Y\to 2^X$. I submit it in a ...
Tony T.'s user avatar
  • 21
3 votes
1 answer
267 views

Example of a Baire Class $1$ function $f$ satisfying $\omega\cdot n<\beta(f)\leq \omega\cdot (n+1)$ for some natural number $n\geq 1.$

Definitions: Let $X$ be a Polish space (separable completely metrizable topological space). A function $f:X\to\mathbb{R}$ is Baire Class $1$ if it is a pointwlise limit of a sequence of continuous ...
Idonknow's user avatar
  • 603
9 votes
1 answer
642 views

Examples of Baire Class $\xi+1$ but not $\xi$ functions for each countable ordinal $\xi.$

We say that $f:\mathbb{R}\to\mathbb{R}$ is of Baire Class $1$ if it is a pointwise limit of a sequence of continuous functions. One can generalize the definition above by taking pointwise limit of ...
Idonknow's user avatar
  • 603
10 votes
0 answers
485 views

Is there a model of set theory in which $\mathfrak p< \mathfrak b < \mathfrak q$?

Is there a model of set theory in which $\mathfrak p< \mathfrak b < \mathfrak q$? Here $\mathfrak p$, $\mathfrak b$, $\mathfrak q$ are small uncountable cardinals: $\mathfrak p$ is the ...
Alexander Osipov's user avatar
4 votes
0 answers
195 views

A kind of 0-1 law?

Suppose that P is a Borel subset of Baire $\times$ Baire, such that for every pair $x,x'$ of reals in the horizontal copy of Baire, if: $x,x'$ are $E_0$-equivalent (that is, $x(n)=y(n)$ for all but ...
Vladimir Kanovei's user avatar
7 votes
1 answer
277 views

Is there a first-countable space containing a closed discrete subset which is not $G_\delta$?

Being motivated by this problem, I am searching for an example of a first-countable regular topological space $X$ containing a closed discrete subset $D$, which is not $G_\delta$ in $X$. It is easy ...
Taras Banakh's user avatar
  • 40.2k
11 votes
1 answer
555 views

Is a locally finite union of $G_\delta$-sets a $G_\delta$-set?

Problem. Let $\mathcal F$ be a locally finite (or even discrete) family of (closed) $G_\delta$-sets in a topological space $X$. Is the union $\cup\mathcal F$ a $G_\delta$-set in $X$? Remark. The ...
Taras Banakh's user avatar
  • 40.2k
5 votes
1 answer
365 views

Equivalent of Lusin's Theorem in Borel setting

Let $X$ be a Polish space, $\mathcal B$ the sigma-algebra of Borel sets. Let $E$ be an aperiodic countable Borel equivalence relation on $X \times X$ (this means that every class of equivalence ...
Shrey's user avatar
  • 53
6 votes
0 answers
168 views

The Fubini property of the $\sigma$-ideal generated by closed subsets of measure zero

Question. Can a Borel subset $B\subset\mathbb R\times \mathbb R$ be covered by countably many closed sets of measure zero in the plane if for every $(a,b)\in\mathbb R\times\mathbb R$ the horisontal ...
Taras Banakh's user avatar
  • 40.2k
2 votes
0 answers
102 views

Is this concrete set generically Haar-null?

This question is related to this problem on MO about generically Haar-null sets in locally compact Polish groups but is more concrete. First we recall the definition of a generically Haar-null set in ...
Taras Banakh's user avatar
  • 40.2k
5 votes
0 answers
212 views

On generically Haar-null sets in the real line

First some definitions. For a Polish space $X$ by $P(X)$ we denote the space of all $\sigma$-additive Borel probability measures on $X$. The space $P(X)$ carries a Polish topology generated by the ...
Taras Banakh's user avatar
  • 40.2k
3 votes
1 answer
458 views

If non-empty player has a winning strategy in Banach-Mazur game BM(X), then it also has in BM(Y)?

Let $f:X\rightarrow Y$ be a continuous, open, surjection function and second player (non-empty) has a winning strategy (not important which one, say for simplicity stationery st.) in $BM(X)$. Then can ...
user117537's user avatar
5 votes
0 answers
138 views

Disjoint covering number of an ideal

Let $\mathcal I$ be a $\sigma$-ideal with Borel base on an uncountable Polish space $X=\bigcup\mathcal I$. Let $\mathrm{cov}(\mathcal I)$ (resp. $\mathrm{cov}_\sqcup(\mathcal I)$) be the smallest ...
Taras Banakh's user avatar
  • 40.2k
3 votes
0 answers
160 views

A characterization of Cauchy filters on countable metric spaces?

Given a filter $\mathcal F$ on a countable set $X$, consider the family $$\mathcal F^+:=\{A\subset X:\forall F\in\mathcal F\;(A\cap F\ne\emptyset)\}.$$ The following characterization is well-known. ...
Taras Banakh's user avatar
  • 40.2k
8 votes
2 answers
703 views

A representation of $F_{\sigma\delta}$-ideals?

First some definitions. By $\mathcal P(\mathbb N)$ we denote the family of all subsets of $\mathbb N$ endowed with the metrizable separable topology generated by the countable base consisting of the ...
Taras Banakh's user avatar
  • 40.2k
13 votes
0 answers
382 views

Is there a continuous map $f:\mathbb R^\omega\to\mathbb R^\omega$ with dense countable preimage $f^{-1}(\mathbb Q^\omega)$?

Let $\mathbb Q^\omega_0:=\{(x_i)_{i\in\omega}\in\mathbb Q^\omega:\exists n\in\omega\;\forall m\ge n\;\;x_m=0\}$ and observe that $\mathbb Q^\omega_0$ is a countable dense set in $\mathbb R^\omega$ (...
Taras Banakh's user avatar
  • 40.2k
17 votes
1 answer
756 views

Is there a continuous function $f:\mathbb R^\omega\to\mathbb R$ with injective restriction $f|\mathbb Q^\omega$?

Question. Is there a continuous function $f:\mathbb R^\omega\to\mathbb R$ whose restriction $f|\mathbb Q^\omega$ is injective?
Taras Banakh's user avatar
  • 40.2k
7 votes
1 answer
202 views

Are σ-sets preserved by Borel isomorphisms?

Recall that a $\sigma$-space is a topological space such that every $F_{\sigma}$-set is $G_{\delta}$-set. $X$ - $\sigma$-set, if $X$ is a $\sigma$-space and it is subset of real line $R$. Let $F$ ...
Alexander Osipov's user avatar
3 votes
4 answers
636 views

Picking a real for every non-empty open set in $\mathbb{R}$

Let ${\cal E}$ denote the collection of open sets of $\mathbb{R}$ with respect to the Euclidean topology. It is well known that $|{\cal E}| = 2^{\aleph_0}$. Is there an injective map $f:{\cal E}\...
Dominic van der Zypen's user avatar
8 votes
1 answer
363 views

Is each $G_\delta$-measurable map $\sigma$-continuous?

Definition. A function $f:X\to Y$ between topological spaces is called $\bullet$ $G_\delta$-measurable if for each open set $U\subset Y$ the preimage $f^{-1}(U)$ is of type $G_\delta$ in $X$; $\...
Taras Banakh's user avatar
  • 40.2k
12 votes
1 answer
309 views

A reference to a theorem on the equivalence of ideals of measure zero in the Cantor cube

I am looking for a reference of the following (true) fact: Theorem. For any two continuous strictly positive Borel probability measures $\mu,\lambda$ on the Cantor cube $2^\omega$ there exists a ...
Taras Banakh's user avatar
  • 40.2k
3 votes
0 answers
142 views

Is an Abelian topological group compact if it is complete and Bohr-compact?

A topological group $G$ will be called Bohr-compact if its Bohr topology (i.e., the largest precompact group topology) is compact and Hausdorff. A topological group $G$ is Bohr-compact if it admits ...
Taras Banakh's user avatar
  • 40.2k
12 votes
0 answers
365 views

Does each compact topological group admit a discontinuous homomorphism to a Polish group?

A compact topological group $G$ is called Van der Waerden if each homomorphism $h:G\to K$ to a compact topological group is continuous. By a classical result of Van der Waerden (1933) the groups $SO(...
Taras Banakh's user avatar
  • 40.2k
4 votes
1 answer
315 views

Is there a topologizable group admitting only Raikov-complete group topologies?

Definition. A group $G$ is called complete (resp. non-topologizable) if each Hausdorff group topology on $G$ is Raikov-complete (resp. discrete). It is clear that each non-topologizable group is ...
Taras Banakh's user avatar
  • 40.2k
3 votes
0 answers
177 views

Is the homeomorphism group of a Polish space a measurable group?

Let $X$ be a Polish space. Let $H(X)$ be the set of homeomorphisms $h \colon X \to X$, equipped with the "evaluation $\sigma$-algebra", namely $\sigma(h \mapsto h(x) : x \in X)$. (Note that for any ...
Julian Newman's user avatar
8 votes
0 answers
425 views

When is the sigma-algebra generated by closed convex sets the same as the Borel sigma-algebra

For which topological vector spaces $E$ do we have the equality between the sigma algebra generated by the closed convex subsets of $E$ and the Borel sigma algebra of $E$ ? More precisely, do we have ...
LCO's user avatar
  • 496
1 vote
1 answer
233 views

Definition of $F_{\sigma}$ sets in terms of $\varepsilon$?

Let $X$ be a metric space. In Borel hierarchy, $\Sigma_{1}^0$ is the set of all open sets in $X$ while $\Pi_{1}^0$ is the set of all closed sets in $X.$ Then at next level, one has $\Sigma_{2}^0 = \{...
Idonknow's user avatar
  • 603
19 votes
1 answer
448 views

Large Borel antichains in the Cantor cube?

Let $2^\omega$ be the Cantor cube $\{0,1\}^\omega$, endowed with the standard compact metrizable topology and the standard product measure, called the Haar measure. The Cantor cube is considered as a ...
Taras Banakh's user avatar
  • 40.2k
14 votes
2 answers
391 views

Given a sequence of reals, we can find a dense sequence avoiding it, but can we find one continuously?

Let $S$ be the set of injective sequences in $\mathbb{R}$: $$S = \{s: \mathbb{N} \rightarrow \mathbb{R}: s(m) \neq s(n) \text{ if }m \neq n\}.$$ Consider $S$ with the topology of pointwise convergence,...
user avatar
5 votes
1 answer
441 views

Covering measure one sets by closed null sets

(The following question arose in a joint research with Adam Przeździecki and Boaz Tsaban.) For a $\sigma$-ideal $\mathcal{I}$ of subsets of the unit interval $[0,1]$, define $$\newcommand{\card}[1]{\...
Piotr Szewczak's user avatar
11 votes
2 answers
973 views

How to show that something is not completely metrizable

I have a Polish space $X$ and a subset $A \subset X$. I know that $A$ is completely metrizable (in its induced topology) if and only if $A$ is a $G_\delta$-set in $X$. This means: If I want to show ...
Tom's user avatar
  • 967
14 votes
3 answers
799 views

Is there a Borel subset of $ \mathbb{R}^{2} $, with finite vertical cross-sections, whose projection onto the first component is non-Borel?

This question is related to another one that I asked two days ago. Question. Does there exist a Borel subset $ M $ of $ \mathbb{R}^{2} $ with the following two properties? The ...
Transcendental's user avatar
6 votes
4 answers
2k views

A simpler proof that compact sets have cardinality continuum?

Is there a simple reason why uncountable compact sets of real numbers have cardinality continuum? I know that this is immediate from the Cantor-Bendixon Theorem, but I wonder whether this consequence ...
Boaz Tsaban's user avatar
  • 2,978
8 votes
1 answer
716 views

When the boundary of any subset is compact?

Let $X$ be a Tychonoff space with no isolated points such that the boundary of any subset of $X$ is compact. Does it mean that $X$ is compact ? (If $X$ is a resolvable space then it is clearly compact....
Lisa_K's user avatar
  • 155
6 votes
1 answer
237 views

Is the space of countable closed covers of the Cantor set analytic?

For an uncountable compact metric space $X$ denote by $K(X)$ be the hyperspace of non-empty compact subsets of $X$, endowed with the Vietoris topology (which is generated by the Hausdorff metric). ...
Taras Banakh's user avatar
  • 40.2k
7 votes
2 answers
349 views

Topological spaces with too many open sets

Is there a Tychonoff space $X$ without isolated points with the following property: For any $a\in X$ and any function $f : X\longrightarrow \mathbb{R}$, if $f$ is continuous on $X\backslash \{a\}$ ...
alex alexeq's user avatar
  • 1,821
25 votes
3 answers
2k views

A rare property of Hausdorff spaces

Is there a Hausdorff topological space $X$ such that for any continuous map $f: X\longrightarrow \mathbb{R}$ and any $x\in \mathbb{R}$, the set $f^{-1}(x)$ is either empty or infinite?
Mark 's user avatar
  • 271
7 votes
1 answer
224 views

Does a continuous map from $\kappa^\omega$ to $[0,1]^\omega$ have a non-scattered fiber?

Question. Let $\kappa>\mathfrak c$ be a cardinal endowed with the discrete topology and $f:\kappa^\omega\to[0,1]^\omega$ be a continuous map. Is there a point $y\in[0,1]^\omega$ whose preimage $f^{-...
Taras Banakh's user avatar
  • 40.2k
6 votes
1 answer
320 views

Bernstein sets of large cardinality

A metrizable space $X$ will be called a generalized Bernstein set if every closed completely metrizable subspace $C$ of $X$ has cardinality $|C|<|X|$. It is well-known that the real line contains ...
Taras Banakh's user avatar
  • 40.2k
5 votes
0 answers
223 views

Do $G_\delta$-measurable maps preserve dimension?

This question (in a bit different form) I leaned from Olena Karlova. Question. Let $f:X\to Y$ be a bijective continuous map between metrizable separable spaces such that for every open set $U\subset ...
Taras Banakh's user avatar
  • 40.2k
7 votes
1 answer
439 views

Product of limit $\sigma$-algebras

Let $X$ and $Y$ be Polish (i.e. Borel subsets of separable completely metrizable) spaces. For a Polish space $Z$, let $\mathscr{S}(Z)$ denote the limit $\sigma$-algebra on $Z$, i.e. the smallest $\...
Jefferson Huang's user avatar
2 votes
1 answer
908 views

Is every path connected space continuously path connected

Recall a topological space $X$ is path connected if for all $x,y \in X$ there is a continuous function $f\colon [0,1] \to X$ such that $f(0)=x$ and $f(1)=y$. Say that $X$ is continuously path ...
Jason Rute's user avatar
  • 6,167
4 votes
1 answer
212 views

Is the following product-like space a Polish space?

Let $\mathcal{M}_1(\mathbb R)$ denote the space of Borel probability measures on $\mathbb R$. The space is a Polish space (a space which admits a complete, separable, metric) using, say the Levy-...
Jason Rute's user avatar
  • 6,167
6 votes
1 answer
175 views

On continuous perturbations of functions of the first Baire class on the Cantor set

Is it true that for any function of the first Baire class $f:X\to\mathbb R$ on the Cantor cube $X=2^\omega$ there is a continuous function $g:X\to[0,1]$ such that the image $(f+g)(X)$ is disjoint with ...
Taras Banakh's user avatar
  • 40.2k