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Are all infinite-dimensional Lie groups noncompact?

Basically what the title says — if a Lie group is infinite-dimensional, is it necessarily noncompact?
Panopticon's user avatar
6 votes
0 answers
186 views

Making the analogy of finiteness and compactness precise

If one asks about the intution behind compact topological spaces, most often one will hear the mantra “Compactness of a topological space is a generalisation of the finiteness of a set.” For example,...
Jannik Pitt's user avatar
  • 1,093
5 votes
2 answers
165 views

Polish space isometric to its hyperspace

For a Polish space $(X,d)$ its hyperspace $(K(X),d_H)$ is also a Polish space. (Here $K(X)$ denotes the set of all nonempty compact subsets of $X$, and the Hausdorff metric $d_H$ is defined by $d_H(K,...
chj's user avatar
  • 157
4 votes
1 answer
208 views

Being contained in a compact set

I have a sequential, hereditarily Lindelöf topological space $\mathcal{X}$, and some subset $A \subseteq \mathcal{X}$. I am interested in the following properties: There is some compact set $B$ with $...
Arno's user avatar
  • 4,096
6 votes
1 answer
180 views

When does base-change in topological spaces preserve quotient maps?

The question when $(-) \times X$ preserves colimits in topological spaces is well-studied. Since it always preserves arbitrary coproducts (disjoint unions), one only has to show when it preserves ...
Lennart Meier's user avatar
9 votes
1 answer
396 views

Do compactly generated spaces have a more direct definition?

Is there an elementary way to define Haussdorf-compactly generated weakly Hausdorff topological spaces in a way that does not need defining topological space first? Weakly Hausdorff sequential spaces ...
saolof's user avatar
  • 1,803
0 votes
0 answers
46 views

Perfectly normal compactification of weak-star dual of Banach space

Let $X$ be an infinite-dimensional (otherwise the answer to my question below is trivial) separable real Banach space with topological dual $X^*$, and denote by $\sigma(X^*,X)$ the weak-star topology ...
weirdo's user avatar
  • 101
5 votes
0 answers
149 views

Does "achieving more GH-distances than some compact space" imply compactness?

Previously asked and bountied at MSE: For complete metric spaces $X,Y$, write $X\trianglelefteq Y$ iff for every complete metric space $Z$ such that the Gromov-Hausdorff distance between $X$ and $Z$ ...
Noah Schweber's user avatar
11 votes
2 answers
402 views

When is a k-space locally compact?

We're looking at the possible cardinal sequences of LCS (locally compact, Hausdorff, scattered) spaces, which has led us to think about taking a quotient of a locally compact, scattered space. A k-...
Carla Simons's user avatar
2 votes
1 answer
448 views

(Dis)prove : if every function with closed graph are continuous then the target space is compact

$(X, \tau_X) $ and $(Y, \tau_Y) $ be two topological spaces. $\forall f\in Y^X$ with $\text{Gr}(f) $ is closed implies $f\in C(X, Y) $. Question : Does this implies $(Y, \tau_Y) $ is compact? ...
Sourav Ghosh's user avatar
9 votes
3 answers
691 views

Structure theorems for compact sets of rationals

Everyone knows the Heine-Borel theorem characterizing compact subsets of Euclidean space. For any $n \in \mathbb N$ a set $A \subseteq \mathbb R^n$ is compact just in case it is closed and bounded (in ...
Corey Bacal Switzer's user avatar
0 votes
1 answer
42 views

Exhaustions of product subsets by smaller product subsets

Let $X$ be a compact metric space, $A,B\subset X$ be subsets and $f\colon X\times X\to \mathbb{R}$ a continuous function that is strictly positive on $A\times B$. Do there exist increasing sequences ...
Federico Vigolo's user avatar
1 vote
1 answer
250 views

Is the restriction of a projection to a compact subset a quotient map?

Let $(X, \mathcal{T}_X)$ and $(Y, \mathcal{T}_Y)$ be topological spaces, $Z = X \times Y$, $\mathcal{T}_Z$ be the product topology on $Z$, $f : Z \to X$ be defined by $f(x, y) = x$, and $C \subset Z$ ...
kaba's user avatar
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0 votes
1 answer
152 views

Is the Čech–Stone compactification of the integers always a retract of an extremally disconnected space?

Probably $\beta \mathbb N$ is not an absolute retract (is there an easy argument for this?), but I'd be interested to know what happens in the class of extremally disconnected (compact) spaces. Is it ...
Tomasz Kania's user avatar
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5 votes
0 answers
235 views

Is this property of continuous maps equivalent to some more familiar condition?

Let $f : X \rightarrow Y$ be a continuous map. Suppose that, for each collection of open sets $\{ V_i \}_{i \in I}\subset X $, $$ \bigcup_{U \subset Y \text{ open}, \ f^{-1}(U) \subset \bigcup_{i \in ...
Cayley-Hamilton's user avatar
4 votes
2 answers
545 views

Arzelà-Ascoli for $C_b(0,1)$? Or more generally, why is that continuous functions "live most naturally" on compact spaces?

I’m wondering if there is a version of Arzelà-Ascoli for continuous functions on not-necessarily compact metric/Hausdorff spaces $X$, i.e. a characterization of the compact subsets of $C_b(X)$ (under ...
D.R.'s user avatar
  • 569
7 votes
2 answers
440 views

Is the union of a compact and the relatively compact components of its complementary in a manifold compact?

I was thinking of a way to prove this and I realised that for my approach the lemma from the title would be useful, and it´s an interesting question on its own. Obviously it is true if the manifold is ...
Saúl RM's user avatar
  • 7,836
6 votes
1 answer
811 views

Is a closed subset of an extremally disconnected set again extremally disconnected?

Let $T$ be a compact Hausdorff extremally disconnected set (so $T$ is a compact Hausdorff space, such that the closure of each open subset is again open). Let $S \subseteq T$ be a closed subset. ...
AlexIvanov's user avatar
0 votes
2 answers
378 views

A question about locally compact spaces

Recently I read a book about linear algebraic group written by Ian Macdonald. There is a conclusion which I can't prove. It says that if $X$ is locally compact Hausdorff space, then $X$ is compact if ...
Fuutorider's user avatar
4 votes
1 answer
223 views

Can Tychonoffs theorem for a countable number of spaces be proven with ZF plus the axiom of (countable) dependent choice?

It can be proven without any form of infinite choice that the product of two compact spaces (and thus any finite product) is compact, while on the other hand, it is well known that the general form of ...
saolof's user avatar
  • 1,803
5 votes
1 answer
154 views

Compactness of symmetric power of a compact space

Suppose I have a compact metric space $(X,d)$ and let $\mathcal{X}=X^K$ be the product space. Consider the equivalence relation $\sim$ on $\mathcal{X}$ given as: for $\alpha,\beta\in \mathcal{X}$, $\...
Sunrit's user avatar
  • 59
1 vote
0 answers
422 views

Is the set of compact operators closed with the strong topology?

It is well-known that the space of compact operators over Banach spaces is closed within the norm topology. My question: Let $X$ be a Banach space. Considering the strong topology (defined by ...
Malik Amine's user avatar
1 vote
1 answer
129 views

Density and compactness of Boolean embeddings

Let A and B be Boolean algebras and $h:A\rightarrow B$ a Boolean embedding. If every element of $B$ can be expressed both as a join of meets and as a meet of joins of elements in $h(A)$, then the ...
IJM98's user avatar
  • 261
1 vote
0 answers
136 views

Relative compactness... but what is the toplogy?

The following Theorem was described in a text I was reading as a compactness result. The proof is probably too advanced for me but I was just wondering with respect to what topology we have ...
edamondo's user avatar
  • 111
8 votes
1 answer
251 views

Characterization of pretty compact spaces

This is a cross post from MSE. I believe that the following problem have already been considered by some sophisticated topologist. Definition 1. A non-compact Hausdorff topological space $X$ is called ...
Norbert's user avatar
  • 1,627
3 votes
2 answers
302 views

Relative compactness in topological spaces (reference request)

Motivation and context: For a subset $S$ of a metric space $(M,d)$, the following are two very classical compactness results in Analysis: 1a) The set $S$ is compact if and only if each sequence in $S$...
Jochen Glueck's user avatar
4 votes
2 answers
269 views

Compact spaces whose compactness does not come from a product of compact spaces

For the (Hausdorff) compact spaces I can think of, compactness is established either using a product of compact spaces (including the Heine-Borel Theorem, the Banach-Alaoglu Theorem, Stone-Čech ...
Cameron Zwarich's user avatar
2 votes
0 answers
2k views

On weak compactness of the unit ball in a reflexive Banach space

It is a well known result in functional analysis that a Banach space $X$ is reflexive if and only if the unit ball is weakly compact (compact in the weak topology). This result is also known as ...
Arian's user avatar
  • 364
0 votes
1 answer
143 views

About the finished, $\aleph_0$...-compactness

Definitions : $(E,d)$ a metric space is finished-compact if any covering of $E$ by open, we can extract a finite subcover $(E,d)$ is $\aleph_0$-compact if for any infinite covering of $E$ by open, we ...
Dattier's user avatar
  • 3,609
1 vote
0 answers
153 views

Subspaces of compact spaces and quotients of Hausdorff spaces

Let $\operatorname{Top}$ be the class of topological spaces. Furthermore, let $\mathcal{U}\subset\operatorname{Top}$ and $\mathcal{V}\subset\operatorname{Top}$ classes satisfying the following ...
cl4y70n____'s user avatar
6 votes
1 answer
522 views

When Stone–Čech compactification is totally disconnected

A topological space $X$ is totally disconnected if the connected components in $X$ are the one-point sets, and a topological space, $X$ is called completely regular exactly in case points can be ...
Arena's user avatar
  • 61
6 votes
1 answer
545 views

Uniqueness of limits and compactness implies closure

It is not difficult to prove that in a Hausdorff topological space every compact set is closed, and almost trivial that if in a topological space X every compact set is closed then X is T1. As ...
Daniel Elessar's user avatar
11 votes
0 answers
252 views

A ZFC-example of a countably compact paratopological group which is not a topological group

Problem. Does there exist a ZFC-example of a countably compact Hausdorff paratopological group which is not a topological group? (The problem posed 27 May 2015 by Alexander Ravsky on page 9 of Volume ...
Lviv Scottish Book's user avatar
1 vote
2 answers
446 views

Extending homeomorphisms between compact metric subsets

Let $X$ be a compact metric, second countable space with finite covering dimension. Let $A,B$ be two closed subsets of $X$. Assume that $h:A\to B$ is a homeomorphism. Is it possible to extend $h$ to a ...
Betti's user avatar
  • 11
6 votes
1 answer
284 views

Is there a compactification with nontrivial connected remainder?

Question: Let $X$ be a continuum and $p \in X$. Under what conditions does there exist a compactification $\gamma (X-p)$ with $\gamma (X-p) - (X-p)$ connected and nondegenerate? Throughout, $X$ is a ...
Daron's user avatar
  • 1,761
3 votes
1 answer
301 views

Checking finite subcover property on dense subset

Let $X$ be a topological space with a dense subset $D\subseteq X$. Suppose that every open cover of $X$ has a finite subfamily which covers $D$. Can I conclude that $X$ itself is compact? The answer ...
Tobias Fritz's user avatar
  • 5,596
11 votes
1 answer
2k views

What are compact objects in the category of topological spaces?

Let $\mathscr C$ be a locally small category that has filtered colimits. Then an object $X$ in $\mathscr C$ is compact if $\operatorname{Hom}(X,-)$ commutes with filtered colimits. On the other hand, ...
R. van Dobben de Bruyn's user avatar
5 votes
2 answers
789 views

Covering compactness in the weak sequential topology

Let $X$ be a real Banach space. Apart from the norm topology, we can consider the following weak topologies on $X$: the weak toplogy, defined as the initial topology with respect to $X^*$. In other ...
Daniel Steck's user avatar
9 votes
2 answers
761 views

On the definition of locally compact for non-Hausdorff spaces

It seems that there are different conventions in the literature as to what is a locally compact space (when the space is not supposed Hausdorff). The two main non equivalent definitions I've seen ...
Phil-W's user avatar
  • 975
13 votes
1 answer
1k views

A topology on $\Bbb R$ where the compact sets are precisely the countable sets

QUESTION. In there a topology on $\Bbb R$ where the compact subsets are precisely the countable subsets? I am trying to create a counterexample to a certain claim, and I found that what I need is a ...
Cauchy's user avatar
  • 233
8 votes
3 answers
580 views

Is there a non-metrizable topological space for which any countably compact subset is compact?

The title is the question : Is there a non-metrizable topological space for which any countably compact subset is compact ? EDIT : non-metrizable and Hausdorff
Michael's user avatar
  • 361
6 votes
2 answers
2k views

How do I prove that compact-open topology is metrizable?

Let $X$ be a $\sigma$-compact topological space and $(Y,d)$ be a metric space. Let $\{K_n\}$ be a sequence of compact subsets of $X$ whose union is $X$. Define $\rho_n(f,g):=\sup \{d(f(z),g(z)): z\...
Rubertos's user avatar
  • 337
6 votes
2 answers
2k views

Is there an easier proof to show that the closed convex hull of a normalized weakly null sequence is weakly compact?

In a paper that I am reading there is a following step: Let $X$ be a Banach space and let $(x_k) \subset X$ be a normalized sequence that converges weakly to $0$. Then $\overline{co}(x_k)$ is a ...
Rauni's user avatar
  • 163
1 vote
0 answers
124 views

Category-theoretic characterization of zero-dimensional spaces

Some background: a zero-dimensional space is one admitting a basis of clopen sets, whereas an extremely disconnected space is one where the closures of open sets are open. In the category CHauss of ...
Andy's user avatar
  • 369
2 votes
1 answer
206 views

A quasicompact space with a net that contains no convergent strict subnet

If $x:\Lambda \rightarrow X$ is a net in a topological space $X$ and $\Lambda '\subseteq \Lambda$ is a cofinal subset of the directed set $\Lambda$, then $x|_{\Lambda '}$ is a subnet of $x$. We call ...
Jonathan Gleason's user avatar
2 votes
0 answers
94 views

On compactness in $C(X)$

Let $X$ be a Tychonoff space. It is well known, that for a family of scalar functions equicontinuity + pointwise boundedness imply relative compactness in $C(X)$ (with compact-open topology). It is ...
erz's user avatar
  • 5,275
3 votes
0 answers
183 views

Which compact topological spaces are homeomorphic to their ultrapower?

It is well known that for any compact metric space $(X, d)$, and any ultrafilter $\mu$ there is a map $i_\mu:\prod_\mu (X, d) \to (X_d)$ in the category of metric spaces and Lipschitz maps where $i_\...
Nate Ackerman's user avatar
3 votes
1 answer
794 views

On compactness in Sion's minimax theorem

Sions minimax theorem (wiki, paper) can be stated as follows: Let $X$ be a compact convex subset of a linear topological space and $Y$ a convex subset of a linear topological space. Let $f$ be a ...
Seyhmus Güngören's user avatar
2 votes
0 answers
182 views

Regularity of Dirac measure on Baire sets [closed]

Suppose $X$ is a locally compact Hausdorff space. Define the Baire sets in $X$, denoted by $\mathcal Ba(X)$, to be the smallest $\sigma$-algebra that contains all compact $G_\delta$ subsets of $X$. ...
Richard Hevener's user avatar
6 votes
2 answers
567 views

Anti-compactness

Let $(X,\tau)$ be a topological space such that $\tau\ne\{\emptyset\ X\}.\ $ We call an open cover $\mathcal{U}$ of $(X,\tau)$ proper if $\ X\notin \mathcal{U}.\ $ Moreover we say that $(X,\...
Dominic van der Zypen's user avatar